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How do you evaluate the definite integral #int e^cosx*sinx# from #[0,pi/4]#?

1 Answer

Feb 20, 2017

# = e - e^(1/sqrt 2)#

Explanation:

#int_0^(pi/4) e^cosx*sinx \ dx#

#= int_0^(pi/4) d/dx (color(red)(-) e^cosx) \ dx#

# = [- e^cosx]_0^(pi/4) #

# = e - e^(1/sqrt 2)#

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