How do you evaluate the definite integral #int(2x^2-x)/x^3# from #[1,e]#? Calculus Introduction to Integration Definite and indefinite integrals 1 Answer Eddie Sep 7, 2016 #= 1 + 1/e# Explanation: #int_1^e(2x^2-x)/x^3 dx# #=int_1^e 2/x-1/x^2 dx# #=[2ln |x| + 1/x ]_1^e # #=(2 + 1/e ) - (0+1 )# #= 1 + 1/e# Answer link Related questions What is the difference between definite and indefinite integrals? What is the integral of #ln(7x)#? Is f(x)=x^3 the only possible antiderivative of f(x)=3x^2? If not, why not? How do you find the integral of #x^2-6x+5# from the interval [0,3]? What is a double integral? What is an iterated integral? How do you evaluate the integral #1/(sqrt(49-x^2))# from 0 to #7sqrt(3/2)#? How do you integrate #f(x)=intsin(e^t)dt# between 4 to #x^2#? How do you determine the indefinite integrals? How do you integrate #x^2sqrt(x^(4)+5)#? See all questions in Definite and indefinite integrals Impact of this question 1144 views around the world You can reuse this answer Creative Commons License