How do you evaluate $tan(-(2pi)/3)$ ?

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Answer 1 · 2018-04-23T01:23:45

$tan(-{2pi} /3 ) = sqrt{3}$

Pro tip: Almost every question in trig involves a 30,60,90 triangle or a 45,45,90 triangle.

We know $-{2pi} /3 = -360^circ/3 = -120^circ$

$sin(-120^circ) = - sqrt{3}/2$

$cos(-120^circ) = -1/2$

$tan(-120^circ) = frac{- sqrt{3} /2 }{- 1/2 } = sqrt{3}$

How do you evaluate tan(-(2pi)/3)tan(-(2pi)/3)?