How do you evaluate $sqrt(log2* 20-log16)$ ?

Question

1709 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-09T14:32:44

The expression can be evaluated to $2.19$ .

$=>sqrt(20log2 - log16)$

Use the rule $alogn = logn^a$ .

$=>sqrt(log(2^20) - log16)$

$=> sqrt(log1,048,576 - log16)$

Now, use the rule $loga - logn = log(a/n)$ .

$=>sqrt(log(65536))$

This can be evaluated, but it cannot be simplified to exact form.

We have

$=>2.19$

Hopefully this helps!

How do you evaluate sqrt(log2* 20-log16) sqrt(log2* 20-log16) ?