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How do you evaluate #Sin(pi/2) + 6 cos(pi/3) #?

1 Answer

Mar 19, 2016

4

Explanation:

#S = sin (pi/2) + 6cos(pi/3)#
Trig table gives ->
#sin (pi/2) = 1#
#cos (pi/3) = 1/2#
Therefor,
#S = 1 + 6(1/2) = 1 + 3 = 4#

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