How do you evaluate sin ((pi)/12)?

1 Answer
P dilip_k
Apr 23, 2016

Using formula sintheta=sqrt(1/2xx(1-cos(2theta)))
sin(pi/12)=sqrt(1/2xx(1-cos(2xxpi/12))
=sqrt(1/2xx(1-cos(pi/6))
=sqrt(1/2xx(1-sqrt3/2)
=sqrt(1/8xx(4-2sqrt3)
=sqrt(1/8xx((sqrt3)^2+1^2-2sqrt3*1)
=sqrt(1/8xx(sqrt3-1)^2)
=1/2xx1/sqrt2xx(sqrt3-1)=(sqrt3-1)/(2sqrt2)

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