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How do you evaluate sin(arccos(-1/3))?

1 Answer

Oct 28, 2015

Evaluate sin (arccos (-1/3)

Ans: #+- (2sqrt2)/3#

Explanation:

#cos x = -1/3# --> Radius of trig circle R = 3

#sin^2 x = R^2 - cos^2 x = 9 - 1/9 = 8/9# --> #sin x = +- (2sqrt2)/3#

#sin (arccos (-1/3)) = +- (2sqrt2)/3#

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