How do you evaluate $sin (\frac{7 π}{4})$ $sin ((7pi)/4)$ ?

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How do you evaluate $sin (\frac{7 π}{4})$ $sin ((7pi)/4)$ ?

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Answer 1 · 2016-04-09T01:55:59

$- \frac{\sqrt{2}}{2}$ $- sqrt2/2$

Explanation:

Trig table and trig unit circle -->
$sin (\frac{7 π}{4}) = sin (- \frac{π}{4} + \frac{8 π}{4}) = sin (- \frac{π}{4} + 2 π) =$ $sin ((7pi)/4) = sin (-pi/4 + (8pi)/4) = sin (-pi/4 + 2pi) =$
$= sin (- \frac{π}{4}) = - sin (\frac{π}{4}) = - \frac{\sqrt{2}}{2}$ $= sin (-pi/4) = - sin (pi/4) = - sqrt2/2$

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How do you evaluate $sin (\frac{7 π}{4})$ $sin ((7pi)/4)$ ?

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