How do you evaluate #sin ((5pi)/4)#?

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How do you evaluate #sin ((5pi)/4)#?

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Answer 1 · 2016-07-31T21:32:14

#-sqrt2/2#

Explanation:

Trig table of special arcs, unit circle, property of supplementary arcs -->
#sin ((5pi)/4) = sin (pi/4 + (4pi)/4) = sin (pi/4 + pi) = - sin (pi/4) =- sqrt2/2#

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How do you evaluate #sin ((5pi)/4)#?

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