How do you evaluate $sin (\frac{- 5 π}{4})$ $sin((-5pi)/4)$ ?

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How do you evaluate $sin (\frac{- 5 π}{4})$ $sin((-5pi)/4)$ ?

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Answer 1 · 2016-04-20T05:09:23

$\frac{\sqrt{2}}{2}$ $sqrt2/2$

Explanation:

Trig table and unit circle -->
$sin (\frac{- 5 π}{4}) = sin (\frac{- 5 π}{4} + \frac{8 π}{4}) = sin (\frac{3 π}{4}) =$ $sin ((-5pi)/4) = sin ((-5pi)/4 + (8pi)/4) = sin ((3pi)/4) =$
$= sin (\frac{π}{4}) = \frac{\sqrt{2}}{2}$ $= sin (pi/4) = sqrt2/2$

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How do you evaluate $sin (\frac{- 5 π}{4})$ $sin((-5pi)/4)$ ?

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