How do you evaluate $sin (\frac{25 π}{6})$ $sin ((25pi)/6)$ ?

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Answer 1 · 2016-06-21T11:16:45

$\frac{1}{2}$ $1/2$

notice that $\frac{25 π}{6} = \frac{(24 + 1) π}{6} = 4 π + \frac{π}{6}$ $(25 pi) / 6 = ((24 + 1) pi) / 6 = 4 pi + pi /6$

so you're just looking at $\frac{π}{6}$ $pi/6$ . you can ignore the 2 full cycles of $2 π$ $2 pi$

$sin (\frac{π}{6}) = \frac{1}{2}$ $sin (pi / 6) = 1/2$

How do you evaluate sin(25π6)sin ((25pi)/6)?