How do you evaluate $sin ((11pi)/2)$ ?

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Answer 1 · 2016-02-28T07:01:48

$-$ 1

sin (2n + 1) $pi$ /2 = ( $-$ 1) ^ n, for any integer n.,
Here, n = 5 and ( $-$ 1)^5 = $-$ 1.

Answer 2 · 2016-02-28T07:02:46

$sin(11pi/2)=-1$

$sin(11pi/2)=sin(6pi-(pi)/2)=sin(-(pi)/2)$

Note $6pi$ is a multiple of $2pi$

As $sin(-pi/2)=-1$

$sin(11pi/2)=-1$

How do you evaluate sin ((11pi)/2)sin ((11pi)/2)?