How do you evaluate #sec(pi/3)#?
1 Answer
Apr 4, 2016
2
Explanation:
# secx = 1/cosx #
#rArr sec(pi/3) = 1/cos(pi/3) # Using the
# pi/3 , pi/6 , pi/2 " triangle " # with sides of length 1 ,
#sqrt3 " and " 2 # we can obtain the exact value of
# cos(pi/3) = 1/2 #
#rArr sec(pi/3) = 1/(1/2) = 2 #
