How do you evaluate #sec(-pi/18) * cos(37pi/18)#?

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How do you evaluate #sec(-pi/18) * cos(37pi/18)#?

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Answer 1 · 2018-03-06T04:32:28

= 1

Explanation:

#sec (- pi/18) = 1/(cos (-pi/18)) = 1/cos (pi/18)#
#cos ((37pi)/18) = cos (pi/18 + (36pi)/18) = cos (pi/18)#
The product transform itself to:
#P = cos (pi/18)/(cos (pi/18)) = 1#

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How do you evaluate #sec(-pi/18) * cos(37pi/18)#?

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