How do you evaluate #sec(-pi)#?

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How do you evaluate #sec(-pi)#?

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Answer 1 · 2016-08-21T17:22:45

#sec(-pi)=1/cos(-pi)#

Explanation:

The #cos# function is an even function, and that means that #cos(-x)=cos x#, for all values of #x#. In particular #cos(-pi)=cos pi = -1#. Then, since #sec (-pi) = 1/cos(-pi)=1/(-1)=-1#

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How do you evaluate #sec(-pi)#?

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