How do you evaluate sec((11pi)/6)?

1 Answer
Oct 25, 2016

(2sqrt3)/3

Explanation:

sec ((11pi)/6) = 1/(cos ((11pi)/6)
Trig table and unit circle -->
cos ((11pi)/6) = cos (-pi/6 + (12pi)/6) = cos (-pi/6 + 2pi) =
= cos (-pi/6) = cos (pi/6) = sqrt3/2
There for:
sec ((11pi)/6) = 2/sqrt3 = (2sqrt3)/3