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How do you evaluate sec (11pi)/3?

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May 7, 2015

#sec (11pi/3) = 1/cos ((11pi)/3)#

Trig unit circle gives:

#cos ((11pi)/3) = cos ((5pi)/3 + 2pi) = cos (pi/3)#

Trig table gives #cos (pi/3) = 1/2#

Then, #sec [(11pi)/3] = 2.#

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