How do you evaluate sec (11pi)/3? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Nghi N. May 7, 2015 sec (11pi/3) = 1/cos ((11pi)/3) Trig unit circle gives: cos ((11pi)/3) = cos ((5pi)/3 + 2pi) = cos (pi/3) Trig table gives cos (pi/3) = 1/2 Then, sec [(11pi)/3] = 2. Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for 140^\circ? How do you find the value of cot 300^@? What is the value of sin -45^@? How do you find the trigonometric functions of values that are greater than 360^@? How do you use the reference angles to find sin210cos330-tan 135? How do you know if sin 30 = sin 150? How do you show that (costheta)(sectheta) = 1 if theta=pi/4? See all questions in Trigonometric Functions of Any Angle Impact of this question 17951 views around the world You can reuse this answer Creative Commons License