How do you evaluate # log10^-2#?

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How do you evaluate # log10^-2#?

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Answer 1 · 2016-03-18T16:59:30

I found #-2# if in base #10#.

Explanation:

We can take the #-2# and put it in front of the log:
#log10^(-2)=-2log10=#
if your log is in base #10# you then get (from the definition of log):
#=-2*1=-2#

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How do you evaluate # log10^-2#?

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