How do you evaluate #log0.003#?

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Answer 1 · 2016-12-18T06:16:03

#bar(3).4771# or #-2.5229#

#log0.003#

= #log(3/1000)#

= #log3-log1000#

= #log3-log10^3#

= #log3-3log10#

= #0.4771-3#

= #bar(3).4771# or #-2.5229#

Note that in #bar(3).4771# while characteristic #3# is negative, mantissa is positive and is #0.4771#