How do you evaluate logx(136)=−(23)? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Bdub Mar 10, 2016 x=216 Explanation: x−23=136 x−23=6−2 (x−23)−32=(6−2)−32 x=63=216 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9x−4=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2log4(x+7)−log4(16)=2? How do you solve 2logx4=16? How do you solve 2+log3(2x+5)−log3x=4? See all questions in Logarithmic Models Impact of this question 3640 views around the world You can reuse this answer Creative Commons License