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How do you evaluate #log_9(3)#?

1 Answer

Mar 22, 2016

#log_9 3##=1/2#

Explanation:

#log_9 3#
#=log3/log 9#-> use property #log_bx = logx/logb#
#=log3/log3^2#
#=log3/(2log3)#-> use property #log_bx^n =nlog_b x#
#=1/2#

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