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How do you evaluate #log_9(1)#?

1 Answer

Nov 15, 2015

I found: #log_9(1)=0#

Explanation:

You need to find a number #x# such that:
#9^x=1#
The value will be #x=0# because #9^0=1#.
So:
#log_9(1)=0#

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