How do you evaluate #log_7 4# using the change of base formula?
1 Answer
May 20, 2017
Explanation:
#"Given " log_b a" then change of base is as follows"#
#• (log_(10)a)/(log_(10)b)#
#rArrlog_7 4=(log_(10)4)/(log_(10)7)~~0.7124#
