How do you evaluate #log_64(1) #? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer George C. Nov 15, 2015 #log_64 1 = 0# Explanation: #log_a 1 = 0# for any base #a# Answer link Related questions What is the exponential form of #log_b 35=3#? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is #log_b 1#? What are some identity rules for logarithms? What is #log_b b^x#? What is the reciprocal of #log_b a#? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 1786 views around the world You can reuse this answer Creative Commons License