How do you evaluate #log_[6](144) - log_[6](4)#?
1 Answer
Apr 4, 2016
Explanation:
Use the identity
#log_x(a) - log_x(b) = log_x(a/b)#
Thus,
#log_6(144) - log_6(4) = log_6(144/4)#
# = log_6(36)#
# = log_6(6^2)#
# = 2#
