How do you evaluate log497+log27(19)÷log64(132)−log32(278)? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer Bdub Mar 22, 2016 log497+log27(19)÷log64(132)−log32(278)=−1710 Explanation: log497+log27(19)÷log64(132)−log32(278) =(log7log72)+(log3−2log33)÷(log2−5log26)−⎛⎜ ⎜⎝log(32)3log(32)⎞⎟ ⎟⎠ =(log72log7)+(−2log33log3)÷(−5log26log2)−⎛⎜⎝3log(32)log(32)⎞⎟⎠ =12−23÷−56−3 =−1710 Answer link Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is log1010? How do I work in log10 in Excel? See all questions in Common Logs Impact of this question 1820 views around the world You can reuse this answer Creative Commons License