How do you evaluate log497+log27(19)÷log64(132)log32(278)?

1 Answer
Mar 22, 2016

log497+log27(19)÷log64(132)log32(278)=1710

Explanation:

log497+log27(19)÷log64(132)log32(278)
=(log7log72)+(log32log33)÷(log25log26)⎜ ⎜log(32)3log(32)⎟ ⎟
=(log72log7)+(2log33log3)÷(5log26log2)3log(32)log(32)
=1223÷563
=1710