How do you evaluate log_49 7 + log_27 (1/9) div log_64 (1/32) - log_(3/2) (27/8)?

1 Answer
Bdub
Mar 22, 2016

log_49 7 +log_27 (1/9) -: log_64 (1/32) - log_(3/2) (27/8) = -17/10

Explanation:

log_49 7 +log_27 (1/9) -: log_64 (1/32) - log_(3/2) (27/8)
=(log7/log7^2) +( log 3^-2 /log3^3)-:(log 2^-5 /log 2^6 )-(log (3/2)^3 /log(3/2))
=(log7/(2 log7)) +( (-2 log 3) /(3 log3))-:((-5 log 2) /(6log 2) )-((3log (3/2)) /log(3/2))
=1/2 -2/3-:-5/6 -3
=-17/10

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