How do you evaluate ${log}_{3} 9 + {log}_{3} 36 - {log}_{3} 4$ $Log_3 9 + log_3 36- log_3 4$ ?

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Answer 1 · 2016-05-15T00:47:20

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Using formula ${log}_{a} m + {log}_{a} n = {log}_{a} (m \times n)$ $" "log_am +log_an =log_a(mxxn)$

${log}_{3} 9 + {log}_{3} 36 - {log}_{3} 4$ $log_3 9 + log_3 36- log_3 4$

$= {log}_{3} (9 \times 36) - {log}_{3} 4$ $=log_3 (9xx36)- log_3 4 " "$

$=log_3( (9xxcancel36^9)/cancel 4) " "$ Using formula $" "log_am +log_an =log_a(mxxn)$

$=log_3 (3^4)=4log_3 3=4xx1=4$

Using formula $" "log_aa =1$

How do you evaluate Log_3 9 + log_3 36- log_3 4log39+log336−log34 Log_3 9 + log_3 36- log_3 4?