How do you evaluate # log_16 57.2#? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer Harish Chandra Rajpoot Jun 24, 2018 1.4594858104727568 Explanation: Applying the logarithms formula, #\log_{a}b=\frac{\log_{10}a}{\log_{10} b}# #\log_{16}57.2# #=\frac{\log_{10}57.2}{\log_{10}16}# #=\frac{\log_{10}57.2}{4\log_{10}2}# #=\frac{1.757396028793024}{1.2041199826559246}# #=1.4594858104727568# Answer link Related questions What is the exponential form of #log_b 35=3#? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is #log_b 1#? What are some identity rules for logarithms? What is #log_b b^x#? What is the reciprocal of #log_b a#? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 2104 views around the world You can reuse this answer Creative Commons License