How do you evaluate # log(1/sqrt1000)#?

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How do you evaluate # log(1/sqrt1000)#?

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Answer 1 · 2016-03-22T15:13:18

#log (1/sqrt1000)=-3/2#

Explanation:

#log (1/sqrt1000)#
#=log(1/sqrt(10^3))#
#=log(1/10^(3/2))#
#=log10^(-3/2)#->Use property #1/x^n =x^-n#
#=-3/2 *log 10#-> Use property #log_bx^n = n* log_bx#
#= -3/2 *1# -> log 10 =1
#= -3/2#

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How do you evaluate # log(1/sqrt1000)#?

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