How do you evaluate #int [x(x^2+1)]dx# for [0, 1]?

Related questions

• What is the difference between definite and indefinite integrals?
• What is the integral of #ln(7x)#?
• Is f(x)=x^3 the only possible antiderivative of f(x)=3x^2? If not, why not?
• How do you find the integral of #x^2-6x+5# from the interval [0,3]?
• What is a double integral?
• What is an iterated integral?
• How do you evaluate the integral #1/(sqrt(49-x^2))# from 0 to #7sqrt(3/2)#?
• How do you integrate #f(x)=intsin(e^t)dt# between 4 to #x^2#?
• How do you determine the indefinite integrals?
• How do you integrate #x^2sqrt(x^(4)+5)#?