How do you evaluate #\frac { 9^ { 2} } { 6^ { 2} }#? Prealgebra Arithmetic and Completing Problems Order of Operations 1 Answer smendyka Mar 5, 2018 See a solution process below: Explanation: #9^2/6^2 = (9 xx 9)/(6 xx 6) = 81/36 = (9 xx 9)/(9 xx 4) = (color(red)(cancel(color(black)(9))) xx 9)/(color(red)(cancel(color(black)(9))) xx 4) = 9/4# Answer link Related questions What is #5-3*(-2) + |-3|#? What is #(3 * 10)^2 -: 5 - 4#? What is #2+2(2)^2(5)+ 8#? What is #14.3 * 2.1 * 8.9#? What is #8+(8+8-:4)+5^2#? How do you use PEMDAS to simplify #3 times 2 - (8+1) #? How do you simplify #3^4+2^3+8(4xx2-5) #? How do you simplify #4times3^2+3times4^2+2(3times4)^2#? How do you solve #30-5(4^2-8รท4-5*2)#? What is #7-3(-8-2) + 6 -:2#? See all questions in Order of Operations Impact of this question 1639 views around the world You can reuse this answer Creative Commons License