How do you evaluate $\frac{1}{3}+\frac{3}{7}-\frac{1}{9}$ ?

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Answer 1 · 2018-03-02T20:37:45

$23/63$

$1/3+3/7−1/9$

$= (1xx21)/(3xx21)+(3xx3)/(7xx3)-(1xx7)/(9xx7)$

[Since Lowest Common Multiple=63]

$= 21/63+9/63-7/63$

$=23/63$

~Hope this helps! :)

How do you evaluate \frac{1}{3}+\frac{3}{7}-\frac{1}{9}\frac{1}{3}+\frac{3}{7}-\frac{1}{9}?