How do you evaluate f(x)=-4x^3+3x-5f(x)=4x3+3x5 at x=2 using direct substitution and synthetic division?

1 Answer
Jul 21, 2018

The remainder is -3131 and the quotient is =-4x^2-8x-13=4x28x13

Explanation:

Let's perform the synthetic division

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color(white)(aaaaa)aaaaa|color(white)(aaaa)aaaa-44color(white)(aaaa)aaaa-88color(white)(aaaa)aaaa-1313color(white)(aaaaa)aaaaacolor(red)(-31)31

The remainder is -3131 and the quotient is =-4x^2-8x-13=4x28x13

(-4x^3+3x-5)/(x-2)=-4x^2-8x-13-31/(x-2)4x3+3x5x2=4x28x1331x2

Apply the remainder theorem

When a polynomial f(x)f(x) is divided by (x-c)(xc), we get

f(x)=(x-c)q(x)+rf(x)=(xc)q(x)+r

Let x=cx=c

Then,

f(c)=0+rf(c)=0+r

Here,

f(x)=-4x^3+3x-5f(x)=4x3+3x5

Therefore,

f(2)=-4*2^3+3*2-5f(2)=423+325

=-32+6-5=32+65

=-31=31