How do you evaluate $f (- 6)$ $f(-6)$ given $f (t) = t^{2} + 2$ $f(t)=t^2+2$ ?

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How do you evaluate $f (- 6)$ $f(-6)$ given $f (t) = t^{2} + 2$ $f(t)=t^2+2$ ?

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Answer 1 · 2017-03-05T14:15:09

$f (- 6) = 38$ $f(-6)=38$

Explanation:

To evaluate f( -6) , substitute t = - 6 into f( t)

$\Rightarrow f (- 6) = {(- 6)}^{2} + 2$ $rArrf(color(red)(-6))=(color(red)(-6))^2+2$

$\Rightarrow f (- 6) = 36 + 2$ $color(white)(rArrf(-6))=36+2$

$\Rightarrow f (- 6) = 38$ $color(white)(rArrf(-6))=38$

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How do you evaluate $f (- 6)$ $f(-6)$ given $f (t) = t^{2} + 2$ $f(t)=t^2+2$ ?

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Explanation:

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How do you evaluate $f (- 6)$ $f(-6)$ given $f (t) = t^{2} + 2$ $f(t)=t^2+2$ ?