How do you evaluate $cot(pi/2)$ ?

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Answer 1 · 2018-06-05T16:38:27

$cot(1/2pi)=0$

We know that

$cottheta=costheta/sintheta$

so

$cot(1/2pi)=cos(1/2pi)/sin(1/2pi)=0/1=0$

Answer 2 · 2018-06-05T16:41:22

$0$

Since $cot(x)=cos(x)/sin(x)$
we get
$cot(pi/2)=cos(pi/2)/sin(pi/2)$
and $cos(pi/2)=0$ and $sin(pi(2)=1$
we get $0$ as the searched result.

How do you evaluate cot(pi/2)cot(pi/2)?