How do you evaluate $cot((11pi)/6)$ ?

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Answer 1 · 2016-09-25T15:46:33

$cot(11pi)/6 = -sqrt3$

$cot((11pi)/6)$

Recall the identity $cottheta=costheta/sintheta$

Using the unit circle, $cos((11pi)/6)=sqrt3/2$ and $sin((11pi)/6)=-1/2$

$cot((11pi)/6)=frac{sqrt3/2}{-1/2}=sqrt3/2 * -2/1=-sqrt3$

How do you evaluate cot((11pi)/6)cot((11pi)/6)?