How do you evaluate $cos (pi/6) + sin (pi/6)$ ?

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Answer 1 · 2018-07-15T17:52:30

$(sqrt3+1)/2$

For problems like these, it helps to memorize the Unit Circle.

On the Unit Circle, the coordinates for $pi/6$ ( $30^@$ ) are

$(sqrt3/2,1/2)$

Where the $x$ -coordinate is the cosine value and the $y$ -coordinate is the sine value.

This means $cos(pi/6)=sqrt3/2$ and $sin(pi/6)=1/2$ . Adding them, we get

$(sqrt3+1)/2$

Hope this helps!

How do you evaluate cos (pi/6) + sin (pi/6) cos (pi/6) + sin (pi/6)?