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How do you evaluate #cos(7/6 pi)#?

1 Answer

A. S. Adikesavan

Apr 22, 2016

#- cos(pi/6)=-sqrt 3/2#.

Explanation:

Cosine in the third quadrant is negative. #cos (pi + theta ) = -cos theta#.

Here, #cos ((7pi)/6)=cos(pi+pi/6)=-cos pi/6=-sqrt 3/2#.

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