How do you evaluate $cos((5pi) / 6) - tan((-7pi) / 4) + sin((13*pi) / 3)$ ?

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Answer 1 · 2016-10-27T08:14:07

$cos((5pi)/6)-tan(-(7pi)/4)+sin((13pi)/3)$

$=cos(pi-pi/6)+tan(2pi-pi/4)+sin(4pi+pi/3)$

$=-cos(pi/6)-tan(pi/4)+sin(pi/3)$

$=-sqrt3/2-1+sqrt3/2$

$=-1$

How do you evaluate cos((5*pi) / 6) - tan((-7*pi) / 4) + sin((13*pi) / 3)cos((5*pi) / 6) - tan((-7*pi) / 4) + sin((13*pi) / 3)?