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How do you evaluate $cos((11pi)/6)$ ?

1 Answer

Apr 7, 2016

$sqrt3/2$

Explanation:

Trig table and trig unit circle -->
$cos ((11pi)/6) = cos (-pi/6 + (12pi)/6) = cos (-pi/6 + 2pi) =$
$= cos (-pi/6) = cos (pi/6) = sqrt3/2$

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