How do you evaluate ${cos}^{- 1} (- \frac{\sqrt{3}}{2})$ $cos ^ -1 (- sqrt3/2)$ ?

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How do you evaluate ${cos}^{- 1} (- \frac{\sqrt{3}}{2})$ $cos ^ -1 (- sqrt3/2)$ ?

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Answer 1 · 2016-11-11T15:35:57

$x = \frac{5 π}{6}, x = \frac{7 π}{6}$ $x=(5pi)/6, x=(7pi)/6$

Explanation:

Use the unit circle, and find where cosine is equal to $(- \frac{\sqrt{3}}{2})$ $(-sqrt3/2)$
Wikipedia

${cos}^{- 1} (- \frac{\sqrt{3}}{2}) = x$ $cos^-1(-sqrt3/2) = x$
$cos x = - \frac{\sqrt{3}}{2}$ $cosx=-sqrt3/2$
$x = \frac{5 π}{6}, x = \frac{7 π}{6}$ $x=(5pi)/6, x=(7pi)/6$

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How do you evaluate ${cos}^{- 1} (- \frac{\sqrt{3}}{2})$ $cos ^ -1 (- sqrt3/2)$ ?

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