How do you evaluate #a(b^x)# given a=-2, b=3, x=1?
1 Answer
Sep 29, 2017
See a solution process below:
Explanation:
Substitute:
#color(red)(-2)# for#color(red)(a)# #color(blue)(3)# for color(blue)(b)##color(green)(1)# for#color(green)(x)#
