How do you evaluate $4tan((-3pi)/4)+sin(-pi/4)$ ?

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Answer 1 · 2016-03-18T13:29:43

$(4 - sqrt2/2)$

Trig unit circle and trig table -->
$tan ((-3pi)/4) = tan (pi/4) = 1$
$4tan ((-3pi)/4) = 4$
$sin (-pi/4) = - sin (pi/4) = - sqrt2/2$

The sum is equal to: $4 - sqrt2/2$

How do you evaluate 4tan((-3pi)/4)+sin(-pi/4)4tan((-3pi)/4)+sin(-pi/4)?