How do you evaluate #(2g - 1) ^2 - 2g + g ^2# for g = 3? Algebra Expressions, Equations, and Functions Variable Expressions 1 Answer Shwetank Mauria Mar 25, 2017 For #g=3#, we have #(2g-1)^2-2g+g^2=28# Explanation: Putting #g=3# in #(2g-1)^2-2g+g^2#, we get #(2xx3-1)^2-2xx3+3^2# = #(6-1)^2-6+9# = #5^2+3# = #25+3# = #28# Answer link Related questions How do you write the variable expression for: a quotient of 2 and the sum of a number and 3 ? What are variables? What are variable expressions? How do you write variable expressions? How do you evaluate variable expressions? How do you simplify the expression #3x-x+4#? How do you write a quotient of a number and 6 as an expression? How do you evaluate the expression #2x+1# for #x=1#? How do you write a product of a number and 2 as an expression? How do you write 5 less than 2 times a number as a variable expression? See all questions in Variable Expressions Impact of this question 1197 views around the world You can reuse this answer Creative Commons License