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How do you evaluate #2 log_2 2 + log_2 8#?

1 Answer

Mar 22, 2016

#2log_2 2+log_2 8=5#

Explanation:

#2log_2 2+log_2 8#
#=2log_2 2+log_2 2^3#
#=2log_2 2+3 log_2 2#->use property #log_bx^n=n*log_bx#
#=2(1)+3(1)#-> use property #log_b b=1#
#=5#

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