How do you evaluate #2\cdot ( - 2) + ( ( - 1) ^ { 2} - 3) ^ { 3}#? Prealgebra Arithmetic and Completing Problems Order of Operations 1 Answer Professor Sam Feb 20, 2017 #-20# Explanation: #2 * (-2) + ((-1)^2 -3)^3# #2 * (-2) + ((-1 * -1) - 3)^3# #2 * (-2) + (1 - 3)^3# #2 * (-2) + -2 ^3# #2 * (-2) + -8# #2 * -10# #= -20# Answer link Related questions What is #5-3*(-2) + |-3|#? What is #(3 * 10)^2 -: 5 - 4#? What is #2+2(2)^2(5)+ 8#? What is #14.3 * 2.1 * 8.9#? What is #8+(8+8-:4)+5^2#? How do you use PEMDAS to simplify #3 times 2 - (8+1) #? How do you simplify #3^4+2^3+8(4xx2-5) #? How do you simplify #4times3^2+3times4^2+2(3times4)^2#? How do you solve #30-5(4^2-8รท4-5*2)#? What is #7-3(-8-2) + 6 -:2#? See all questions in Order of Operations Impact of this question 1325 views around the world You can reuse this answer Creative Commons License