How do you evaluate #10 ^ (2log6)#? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer Cesareo R. Aug 20, 2016 #36# Explanation: #10 ^ (2log_{10}6) = (10^{log_{10}6})^2=6^2=36# Answer link Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 1935 views around the world You can reuse this answer Creative Commons License