How do you draw $- 330^{\circ}$ $-330^circ$ in standard position and find one positive and one negative angle that is coterminal to the given angle?

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How do you draw $- 330^{\circ}$ $-330^circ$ in standard position and find one positive and one negative angle that is coterminal to the given angle?

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Answer 1 · 2018-02-22T00:51:50

Negative: $- 690^{\circ}$ $-690^@$
Positive: $30^{\circ}$ $30^@$

Explanation:

Since, + angles go counter-clockwise, negative ones go clockwise.
We go 330 degrees clockwise to get:
enter image source here

The black shows the negative angle, yellow/orange the positive. We can get another negative/positive by adding / subtracting $360^{\circ}$ $360^@$ , as I did to get the $- 690^{\circ}$ $-690^@$ solution.

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How do you draw $- 330^{\circ}$ $-330^circ$ in standard position and find one positive and one negative angle that is coterminal to the given angle?

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Explanation:

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How do you draw −330∘-330^circ in standard position and find one positive and one negative angle that is coterminal to the given angle?

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How do you draw $- 330^{\circ}$ $-330^circ$ in standard position and find one positive and one negative angle that is coterminal to the given angle?