How do you divide x3+7x23x+4)÷(x+2) and identify any restrictions on the variable?

1 Answer
Dec 20, 2017

x2+5x13+30x+2(x2)

Explanation:

one way is to use the divisor as a factor in the numerator

consider the numerator

x2(x+2)2x2+7x23x+4

=x2(x+2)+5x(x+2)10x3x+4

=x2(x+2)+5x(x+2)13(x+2)+26+4

=x2(x+2)+5x(x+2)13(x+2)+30

quotient =x2+5x13, remainder =30

x3+7x23x+4x+2

=x2+5x13+30x+2(x2)