How do you divide x3+7x2−3x+4)÷(x+2) and identify any restrictions on the variable?
1 Answer
Dec 20, 2017
Explanation:
one way is to use the divisor as a factor in the numerator
consider the numerator
x2(x+2)−2x2+7x2−3x+4
=x2(x+2)+5x(x+2)−10x−3x+4
=x2(x+2)+5x(x+2)−13(x+2)+26+4
=x2(x+2)+5x(x+2)−13(x+2)+30
quotient =x2+5x−13, remainder =30
⇒x3+7x2−3x+4x+2
=x2+5x−13+30x+2→(x≠−2)