How do you divide $(x^{3} - 6 x^{2} - 6 x + 9) \div (x + 1)$ $(x^3-6x^2-6x+9)div(x+1)$ using synthetic division?

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How do you divide $(x^{3} - 6 x^{2} - 6 x + 9) \div (x + 1)$ $(x^3-6x^2-6x+9)div(x+1)$ using synthetic division?

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Answer 1 · 2016-11-12T08:12:44

The quotient is $= x^{2} - 7 x + 1$ $=x^2-7x+1$
The remainder is $= 8$ $=8$

Explanation:

let's do the long division

$a a a a$ $color(white)(aaaa)$ $x^{3} - 6 x^{2} - 6 x + 9$ $x^3-6x^2-6x+9$ $a a$ $color(white)(aa)$ $∣$ $∣$ $x + 1$ $x+1$
$a a a a$ $color(white)(aaaa)$ $x^{3} + x^{2}$ $x^3+x^2$ $a a a a a a a a a a a$ $color(white)(aaaaaaaaaaa)$ $∣$ $∣$ $x^{2} - 7 x + 1$ $x^2-7x+1$
$a a a a a$ $color(white)(aaaaa)$ $0 - 7 x^{2} - 6 x$ $0-7x^2-6x$
$a a a a a a a$ $color(white)(aaaaaaa)$ $- 7 x^{2} - 7 x$ $-7x^2-7x$
$a a a a a a a a a a a$ $color(white)(aaaaaaaaaaa)$ $0 + x + 9$ $0+x+9$
$a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaa)$ $+ x + 1$ $+x+1$
$a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaa)$ $+ 0 + 8$ $+0+8$

So the quotient is $= x^{2} - 7 x + 1$ $=x^2-7x+1$

and the remainder $= 8$ $=8$

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How do you divide $(x^{3} - 6 x^{2} - 6 x + 9) \div (x + 1)$ $(x^3-6x^2-6x+9)div(x+1)$ using synthetic division?

1 Answer

Explanation:

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How do you divide (x3−6x2−6x+9)÷(x+1)(x^3-6x^2-6x+9)div(x+1) using synthetic division?

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How do you divide $(x^{3} - 6 x^{2} - 6 x + 9) \div (x + 1)$ $(x^3-6x^2-6x+9)div(x+1)$ using synthetic division?